Home > JavaScript Questions > What will the code below output to the console and why?
var myObject = {
foo: "bar",
func: function() {
var self = this;
console.log("outer func: this.foo = " + this.foo);
console.log("outer func: self.foo = " + self.foo);
(function() {
console.log("inner func: this.foo = " + this.foo);
console.log("inner func: self.foo = " + self.foo);
}());
}
};
myObject.func();
The above code will output the following to the console:
outer func: this.foo = bar
outer func: self.foo = bar
inner func: this.foo = undefined
inner func: self.foo = bar
In the outer function, both this and self refer to myObject and therefore
both can properly reference and access foo.
In the inner function, though, this no longer refers to myObject. As a
result, this.foo is undefined in the inner function, whereas the reference
to the local variable self remains in scope and is accessible there.